document.write( "Question 1081699: Construct frequency distribution table of
\n" ); document.write( "24.2,28.9,18.6,19.7,25.2,22.1,29.9,32.3,32.3,31.4,29.9,22.5,18.5,25.3,25.7,27.5,23.2,20.1,28.1,27.4,23.4,18.7,19.6,28.2,32.2,25.8,19.8,26.8,27.5,27.3,23.0,32.6,24.4,34.2,28.8,25.2,20.8,25.4,25.3,20.6,25.5,26.1,24.8,32.5,24.7,25.6,29.5,26.3,19.3,31.8,22.0,26.2,27.8,30.8,18.7,25.2,27.6,21.2,27.4,25.8,33.9,26.7,27.6,26.8,20.5,25.2,21.2,19.5,26.4,25.2,20.4,20.4,27.2,20.6,25.5,27.9,38.7,22.8,20.9,21.9,26.6,22.2,20.8,21.2,19.1,18.9,21.3,21.7,34.5,26.8,24.0,24.7,22.1,20.7,25.5,37.3,24.8,25.3,25.9,26.5 \n" ); document.write( "

Algebra.Com's Answer #695767 by jim_thompson5910(35256) $\"\"$ $\"About$

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If you start at 15, and the class width is 5, then you'd have this grouped frequency table
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Class Interval	Frequency
15-19.9	11
20-24.9	32
25-29.9	44
30-34.9	11
35-39.9	2

\n" ); document.write( "The class intervals are accurate to 1 decimal place. To construct such a table, you can count the values by hand and see which class interval they land in. For instance, there are 11 values that are between 15 and 19.9 (inclusive of both endpoints). Doing it by hand is a pain with this many values, which is why spreadsheet programs such as excel make the task so much easier. \n" ); document.write( "

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