document.write( "Question 95532: The length of a rectangle is 5 cm more than 4 times its width. If the area of the rectangle is 80 cm2, find the dimensions of the rectangle to the nearest thousandth.\r
\n" ); document.write( "\n" ); document.write( "Please Help! \n" ); document.write( "
Algebra.Com's Answer #69574 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
width=x
\n" ); document.write( "length=5+4x
\n" ); document.write( "(x)(5+4x)=80
\n" ); document.write( "5x+4x^2-80=0
\n" ); document.write( "4x^2+5x-80=0
\n" ); document.write( "using the quadratic equation we get;
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "x=(-5+-sqrt[5^2-4*4*-80])/2*4
\n" ); document.write( "x=(-5+-sqrt[25+1280])/8
\n" ); document.write( "x=(-5+-sqrt[1305])/8
\n" ); document.write( "x=(-5+-36.125)/8
\n" ); document.write( "x=(-5+36.125)/8
\n" ); document.write( "x=(-5+36.125)/8
\n" ); document.write( "x=31.125/8
\n" ); document.write( "x=3.89 answer.
\n" ); document.write( "x=(-5-36.125)/8
\n" ); document.write( "x=-41.125/8
\n" ); document.write( "x=-5.14 answer.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );