document.write( "Question 1081630: A ball is kicked off of the roof of a 40 foot tall building with an initial vertical velocity of 16 feet per second . The balls distance from the ground can be modeled by the equation h =- 16t^2+ vt+s.
\n" ); document.write( "A. Find the height of the ball after 1.5 seconds .
\n" ); document.write( "B. Determine the maximum height of the ball and the time that passes before the ball reaches that height \n" ); document.write( "
Algebra.Com's Answer #695712 by ankor@dixie-net.com(22740)\"\" \"About 
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A ball is kicked off of the roof of a 40 foot tall building with an initial vertical velocity of 16 feet per second . The balls distance from the ground can be modeled by the equation h =- 16t^2+ vt+s.
\n" ); document.write( "vt = 16; s = 40
\n" ); document.write( " h = -16t^2 + 16t + 40
\n" ); document.write( " A. Find the height of the ball after 1.5 seconds .
\n" ); document.write( "t = 1.5
\n" ); document.write( "h = -16(1.5^2) + 16(1.5) + 40
\n" ); document.write( "h = -16(2.25) + 24 + 40
\n" ); document.write( "h = -36 + 64
\n" ); document.write( "h = 28 ft after 1.5 sec
\n" ); document.write( " B. Determine the maximum height of the ball and the time that passes before the ball reaches that height
\n" ); document.write( "Max occurs on the axis of symmetry. find it; x = -b/(2a)
\n" ); document.write( "\"t+=+%28-16%29%2F%282%28-16%29%29\"
\n" ); document.write( "t = .5 seconds
\n" ); document.write( "Find the height at .5 sec
\n" ); document.write( "h = -16(.5^2) + 16(.5) + 40
\n" ); document.write( "h = -16(.25) + 48
\n" ); document.write( "h = -4 + 48
\n" ); document.write( "h = 44 ft is the max height \n" ); document.write( "
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