document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081633>Question 1081633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Why would 3>=-6 become o>=-9 ?\r<BR>\n" );
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document.write( "The problem is ....  3(1-x) >= -3(x+2)  why wouldn't it be 3 >= -6  (all real numbers)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695693 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(1 - x) >= -3(x + 2) distribute the 3 and -3 (Distributive Property of Multiplication)<BR>\n" );
document.write( "3 - 3x >= -3x + -6<BR>\n" );
document.write( "subtract 3 on both sides:<BR>\n" );
document.write( "-3x >= -3x + -9<BR>\n" );
document.write( "Now add 3x on both sides:<BR>\n" );
document.write( "-3x + 3x >= -3x + 3x - 9<BR>\n" );
document.write( "0x, or just 0, >= -9<BR>\n" );
document.write( "This is correct because 0 IS greater than -9 (I wrote bigger in the picture I made you, it should say greater)<BR>\n" );
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