document.write( "Question 1081610: The average time to complete a race last weekend was 47 minutes with a standard deviation of 4. One of the participants, Anne, finished the race in 41 minutes. What percentage of the racers took longer than Anne to complete the race? \n" ); document.write( "
Algebra.Com's Answer #695687 by Boreal(15235)\"\" \"About 
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z value is (x-mean)/sd=(41-47)/4=-1.5
\n" ); document.write( "The probability for that z-value is 0.0668,so 0.9332 or 93.32% of the racers took longer than she did.
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