document.write( "Question 1081579: A submarine left the Azores and traveled
\n" ); document.write( "west. Three hours later an aircraft carrier
\n" ); document.write( "left traveling 3 mph faster in an effort to
\n" ); document.write( "catch up to it. After seven hours the aircraft
\n" ); document.write( "carrier finally caught up. Find the
\n" ); document.write( "submarine's average speed.
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Algebra.Com's Answer #695643 by ankor@dixie-net.com(22740)\"\" \"About 
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A submarine left the Azores and traveled west.
\n" ); document.write( " Three hours later an aircraft carrier left traveling 3 mph faster in an effort to catch up to it.
\n" ); document.write( " After seven hours the aircraft, carrier finally caught up.
\n" ); document.write( " Find the submarine's average speed.
\n" ); document.write( ":
\n" ); document.write( "From the information given, we know
\n" ); document.write( "Sub travel time = 10 hrs
\n" ); document.write( "Car travel time = 7 hr
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\n" ); document.write( "let s = sub speed
\n" ); document.write( "then
\n" ); document.write( "(s+3) = car speed
\n" ); document.write( ":
\n" ); document.write( "When carrier catches the sub, they each will have traveled the same distance
\n" ); document.write( "Write a distance equation; dist = time * speed
\n" ); document.write( "10s = 7(s+3)
\n" ); document.write( "10s = 7s + 21
\n" ); document.write( "10s - 7s = 21
\n" ); document.write( " 3s = 21
\n" ); document.write( " s = 21/3
\n" ); document.write( " s = 7 mph is the speed of the sub
\n" ); document.write( ":
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\n" ); document.write( "Check this, find the dist of each
\n" ); document.write( "10*7 = 70 mi
\n" ); document.write( "7(7+3) = 70 mi
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