document.write( "Question 1081579: A submarine left the Azores and traveled
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document.write( "west. Three hours later an aircraft carrier
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document.write( "left traveling 3 mph faster in an effort to
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document.write( "catch up to it. After seven hours the aircraft
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document.write( "carrier finally caught up. Find the
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document.write( "submarine's average speed. \n" );
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Algebra.Com's Answer #695643 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A submarine left the Azores and traveled west. \n" ); document.write( " Three hours later an aircraft carrier left traveling 3 mph faster in an effort to catch up to it. \n" ); document.write( " After seven hours the aircraft, carrier finally caught up. \n" ); document.write( " Find the submarine's average speed. \n" ); document.write( ": \n" ); document.write( "From the information given, we know \n" ); document.write( "Sub travel time = 10 hrs \n" ); document.write( "Car travel time = 7 hr \n" ); document.write( "; \n" ); document.write( "let s = sub speed \n" ); document.write( "then \n" ); document.write( "(s+3) = car speed \n" ); document.write( ": \n" ); document.write( "When carrier catches the sub, they each will have traveled the same distance \n" ); document.write( "Write a distance equation; dist = time * speed \n" ); document.write( "10s = 7(s+3) \n" ); document.write( "10s = 7s + 21 \n" ); document.write( "10s - 7s = 21 \n" ); document.write( " 3s = 21 \n" ); document.write( " s = 21/3 \n" ); document.write( " s = 7 mph is the speed of the sub \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, find the dist of each \n" ); document.write( "10*7 = 70 mi \n" ); document.write( "7(7+3) = 70 mi \n" ); document.write( " \n" ); document.write( " |