document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081536>Question 1081536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of two supplementary angles is 102^0. Find the angle (Hint:use simultaneous equation) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695583 by </B><A HREF=/tutors/aboutme.mpl?userid=chen><B>chen(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x an y be the angles (x>y).<BR>\n" );
document.write( "Then x+y = 180<BR>\n" );
document.write( " and x-y = 102.\r<BR>\n" );
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document.write( "By adding them together, we get 2x = 282 so x=141 and y = 180-141 = 39.<BR>\n" );
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