document.write( "Question 95455: The length of a rectangle is 5 cm more than 4 times its width. If the area of the rectangle is 80 cm2, find the dimensions of the rectangle to the nearest thousandth.\r
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document.write( "Please Help! \n" );
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Algebra.Com's Answer #69558 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let w=width\r \n" ); document.write( "\n" ); document.write( "Then length (l)=4w+5 (we are told this)\r \n" ); document.write( "\n" ); document.write( "Area of a rectangle =length x width. So we have\r \n" ); document.write( "\n" ); document.write( "80=w(4w+5) get rid of parens\r \n" ); document.write( "\n" ); document.write( "80=4w^2+5w subtract 80 from both sides\r \n" ); document.write( "\n" ); document.write( "4w^2+5w-80=80-80 or\r \n" ); document.write( "\n" ); document.write( "4w^2+5w-80=0---------quadratic in standard form\r \n" ); document.write( "\n" ); document.write( "Solve using the quadratic formula:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Disregard the negative value for x. Lengths and widths are positive\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( " \n" ); document.write( "~80=~80\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |