document.write( "Question 95455: The length of a rectangle is 5 cm more than 4 times its width. If the area of the rectangle is 80 cm2, find the dimensions of the rectangle to the nearest thousandth.\r
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Algebra.Com's Answer #69558 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let w=width\r
\n" ); document.write( "\n" ); document.write( "Then length (l)=4w+5 (we are told this)\r
\n" ); document.write( "\n" ); document.write( "Area of a rectangle =length x width. So we have\r
\n" ); document.write( "\n" ); document.write( "80=w(4w+5) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "80=4w^2+5w subtract 80 from both sides\r
\n" ); document.write( "\n" ); document.write( "4w^2+5w-80=80-80 or\r
\n" ); document.write( "\n" ); document.write( "4w^2+5w-80=0---------quadratic in standard form\r
\n" ); document.write( "\n" ); document.write( "Solve using the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+5%5E2-4%2A4%2A%28-80%29+%29%29%2F%282%2A4%29+\"
\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%281305%29%29%2F%288%29\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+36.125%29%2F%288%29\" \r
\n" ); document.write( "\n" ); document.write( "Disregard the negative value for x. Lengths and widths are positive\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B36.125%29%2F%288%29\"
\n" ); document.write( "\"x+=+31.125%2F%288%29\"
\n" ); document.write( "\"x+=+3.891\"cm--------------------width
\n" ); document.write( "\"4x%2B5=4%283.891%29%2B5+=+20.562\"cm-------------length\r
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\n" ); document.write( "\"A=l%2Aw=3.891%2A20.562=80.008\" cm
\n" ); document.write( "~80=~80\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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