document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95528>Question 95528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "I have 2 questions, Im so coonfused.\r<BR>\n" );
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document.write( "1)   Let P be the point on the unit circle U that corresponds to an angle t. Find the exact coordinates(x,y) of P and the exactvalues of the trigonometric functions at angle t. Use sqrt (2) for the square root of 2 and if the value of a trigonometric function is undefined, enter und. t=(-pi)\r<BR>\n" );
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document.write( "x=?  y=?<BR>\n" );
document.write( "sin(t)=?,cos(t)=?,tan(t)=?,csc(t)=?, sec(t)=?, cot(t)=?\r<BR>\n" );
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document.write( "2)    Use the fundmental identities to find the values of the trigonometric functions(as decimal values within 0.001) for the give conditions.\r<BR>\n" );
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document.write( "sin(t)=0.6, cos(t)<0<BR>\n" );
document.write( "sin(t)=?,cos(t)=?,tan(t)=?,csc(t)=?, sec(t)=?, cot(t)=? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69550 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the circumference of any circle is 2pi radians.<BR>\n" );
document.write( "An angle of pi (-1,0)is 180 degrees from the standard position (1,0) on the circumference going counterclockwise.<BR>\n" );
document.write( "-pi (-1,0) has the same coordinates but arrives there from the standard position going clockwise.<BR>\n" );
document.write( "In the unit circle sin=y cos=x & tan=y/x<BR>\n" );
document.write( "In this case sin=0 cos=-1 tan=0/-1=0 csc=1/0=und. sec=1/-1=-1 cot=-1/0=und<BR>\n" );
document.write( "We derived all of these above formulas from (-1,0).<BR>\n" );
document.write( "Easy, huh!<BR>\n" );
document.write( "2nd question:<BR>\n" );
document.write( "sin(t)=0.6, cos(t)<0<BR>\n" );
document.write( "sin is + in quadrants 1 and 2<BR>\n" );
document.write( "cos is <0 (ie. negative) in quadrants 2 and 3<BR>\n" );
document.write( "So the terminal side of the angle is in quadrant 2<BR>\n" );
document.write( "y=.6<BR>\n" );
document.write( "If we draw a right triangle in quadrant 2 using the suppliment of the angle as our reference angle then y=.6 is the opposite side and the hypotenuse=1. In the unit circle the hypotenuse is always 1 and is always positive!<BR>\n" );
document.write( "Now we can find x which is negative (quadrant 2).<BR>\n" );
document.write( "y^2+x^2=c^2<BR>\n" );
document.write( ".36+x^2=1<BR>\n" );
document.write( "x^2=1-.36=.64<BR>\n" );
document.write( "x=-.8<BR>\n" );
document.write( "cos=-.8 tan=-.6/.8=-.75 cot=-.8/.6 csc=1/.6 sec=-1/.8=-1.25<BR>\n" );
document.write( "EdJones\r<BR>\n" );
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document.write( " </SPAN>\n" );
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