document.write( "Question 95472: 3y/2+y/6=10/3 solve the linear equation?
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Algebra.Com's Answer #69546 by jayanthihemkos@yahoo.com(87) $\"\"$ $\"About$

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3y/2+y/6=10/3 solve the linear equation?\r
\n" ); document.write( "\n" ); document.write( "L.C.D of 2, 6 , 3 is 6 \r
\n" ); document.write( "\n" ); document.write( "Multiply the equation by 6 \r
\n" ); document.write( "\n" ); document.write( "3y/2*6+y/6*6=10/3*6\r
\n" ); document.write( "\n" ); document.write( "Multiplying by the L.C.D will remove the fraction\r
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\n" ); document.write( "\n" ); document.write( "3y *3 + y = 20\r
\n" ); document.write( "\n" ); document.write( "9y +y = 20\r
\n" ); document.write( "\n" ); document.write( "10y = 20 \r
\n" ); document.write( "\n" ); document.write( "10y/10 = 20/10\r
\n" ); document.write( "\n" ); document.write( "y = 2\r
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\n" ); document.write( "consider the equation and pluggin the value of y in it\r
\n" ); document.write( "\n" ); document.write( "3y/2+y/6=10/3 \r
\n" ); document.write( "\n" ); document.write( "3(2)/2 +2/6 = 10/3\r
\n" ); document.write( "\n" ); document.write( "6/2 +2/6 = 10/3\r
\n" ); document.write( "\n" ); document.write( "3 +1/3 = 10/3\r
\n" ); document.write( "\n" ); document.write( "(3*3 +1)/3 = 10/3 \r
\n" ); document.write( "\n" ); document.write( "(9+1)/3 = 10/3\r
\n" ); document.write( "\n" ); document.write( "10/3 = 10/3\r
\n" ); document.write( "\n" ); document.write( "LHS = RHS\r
\n" ); document.write( "\n" ); document.write( "Hence y = 2 is the solution\r
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