document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081423>Question 1081423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is my question, I am Richard and I am X year old. My father is three times my age, my mother is 2 years younger than my father and my sister is 1 year older than me. The total of our ages is 103. Form an equation in X and solve it to find the age of every member of the family. Also can you give me the working if it is no trouble.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695453 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Richard = X [years old]<BR>\n" );
document.write( "Father = 3X [3 times Richard's age]<BR>\n" );
document.write( "Mother = 3X - 2 [2 years younger than Father]<BR>\n" );
document.write( "Sister = X + 1 [one year older than Richard]<BR>\n" );
document.write( "The sum of the ages is 103:<BR>\n" );
document.write( "X + 3X + 3X - 2 + X + 1 = 103<BR>\n" );
document.write( "Now solve for X:<BR>\n" );
document.write( "8X - 1 = 103<BR>\n" );
document.write( "X = 104/8 = 13<BR>\n" );
document.write( "So Richard is 13 years old.  The other ages can be computed from the relationships above. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );