document.write( "Question 1081393: log4[log4(2x)]=1 \n" ); document.write( "
Algebra.Com's Answer #695408 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
log4[log4(2x)]=1\r
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\n" ); document.write( "\n" ); document.write( "I assume you want to solve for x. In the future you should clearly ask your question. \r
\n" ); document.write( "\n" ); document.write( "\"+log%284%2C%28log%284%2C%282x%29%29%29%29=1+\"\r
\n" ); document.write( "\n" ); document.write( "Raise 4 to both sides:
\n" ); document.write( "\"+4%5Elog%284%2C%28log%284%2C%282x%29%29%29%29+=+4%5E1+\"
\n" ); document.write( "This simplifies to:
\n" ); document.write( "\"+log%284%2C%282x%29%29+=+4+\"
\n" ); document.write( "Again, raise 4 to both sides:
\n" ); document.write( "\"+4%5Elog%284%2C%282x%29%29+=+4%5E4+\"
\n" ); document.write( "This simplifies to:
\n" ); document.write( "\"++2x+=+256+\"
\n" ); document.write( "\"++x+=+highlight%28128%29+\"\r
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( "Check: \"log%284%2C+%28log%284%2C%282%2A128%29%29%29%29+=+log%284%2C+%284%29%29+=+1+\"
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