document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081342>Question 1081342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please explain and answer these two homework questions: \r<BR>\n" );
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document.write( "1) If r(x)= -2x^2-3x-3, find r(-4) \r<BR>\n" );
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document.write( "2) -3{((-4-1)-(-6^0-2)-1)-1} + or - sqroot of 9 \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695371 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r(x)= -2x^2-3x-3, find r(-4) <BR>\n" );
document.write( "r(-4)=-2(-4)^2-3(-4)-3=-32+12=3=-23<BR>\n" );
document.write( "-3{((-4-1)-(-6^0-2)-1)-1} + or - sqroot of 9 <BR>\n" );
document.write( "-3((-5)-(-1-2)-1)-1) +/-3<BR>\n" );
document.write( "-3(-4)+/- 3<BR>\n" );
document.write( "12+/-3<BR>\n" );
document.write( "9, 15 </SPAN>\n" );
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