document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080884>Question 1080884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An amount of shs 2000 is invested at an interest if 5% per month. If shs 200 is added at the beginning of each successive month but with no withdraws,  <BR>\n" );
document.write( "1.Give an expression for the value accumulated after n months.<BR>\n" );
document.write( "2.After how many months will the amount have accumulated first exceed shs. 42000?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695195 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total=2000(1+(.05/12))^n-1/(0.05/12)<BR>\n" );
document.write( "42000=2000(1+(.05/12))^n-1/(0.05/12)<BR>\n" );
document.write( "divide by 2000 and multiply by (0.05/12)<BR>\n" );
document.write( "0.0875=1.00416667^n-1<BR>\n" );
document.write( "1.0875=1.00416667^n<BR>\n" );
document.write( "ln both sides<BR>\n" );
document.write( "0.0839=n *0.00416<BR>\n" );
document.write( "n=20.18 months; 21 months ANSWER<BR>\n" );
document.write( "Check with 20 and 21<BR>\n" );
document.write( "$41623.63 and $43797.06 </SPAN>\n" );
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