document.write( "Question 95273: 1.How many liters of 22% salt solution must be added to 75 liters of 67% salt to get a 47% salt solution?\r
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document.write( "2. How many gallons of a 40% alcohol solution should be mixed with 15 gallons of 80% solution to obtain a 60% alcohol solution? \n" );
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Algebra.Com's Answer #69519 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1.How many liters of 22% salt solution must be added to 75 liters of 67% salt to get a 47% salt solution? \n" ); document.write( ": \n" ); document.write( "Let x = no. of liters of 22% solution: \n" ); document.write( ": \n" ); document.write( "Resulting amt = (x+75) \n" ); document.write( ": \n" ); document.write( ".22x + .67(75) = .47(x+75) \n" ); document.write( ".22x + 50.25 = .47x + 35.25 \n" ); document.write( ".22x - .47x = 35.25 - 50.25 \n" ); document.write( "-.25x = -15 \n" ); document.write( "x = -15/-.25 \n" ); document.write( "x = +60 liters of 22% solution: \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( ".22(60) + .67(75) = .47(60+75) \n" ); document.write( " 13.2 + 50.25 = .47(135) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "2. How many gallons of a 40% alcohol solution should be mixed with 15 gallons of 80% solution to obtain a 60% alcohol solution? \n" ); document.write( ": \n" ); document.write( "Do this one exactly the same way. Email me if you need help on it. \n" ); document.write( " |