document.write( "Question 1081080: If tan x + cot x = 2, then find the value tan^17 x + cot^17 x \n" ); document.write( "
Algebra.Com's Answer #695169 by ikleyn(52864)\"\" \"About 
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document.write( "If tan(x) + cot(x) = 2, then \r\n" );
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document.write( "   \"sin%28x%29%2Fcos%28x%29\" + \"cos%28x%29%2Fsin%28x%29\" = 2,  ---->\r\n" );
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document.write( "   \"sin%5E2%28x%29%2F%28sin%28x%29%2Acos%28x%29%29\" + \"cos%5E2%28x%29%2F%28sin%28x%29%2Acos%28x%29%29\" = 2,  ---->\r\n" );
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document.write( "   \"%28sin%5E2%28x%29+%2B+cos%5E2%28x%29%29%2F%28sin%28x%29%2Acos%28x%29%29\" = 2,  ---->\r\n" );
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document.write( "   \"1%2F%28sin%28x%29%2Acos%28x%29%29\" = 2,\r\n" );
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document.write( "   2sin(x)*cos(x) = 1  --->  sin(2x) = 1  --->  2x = \"pi%2F2\"  --->  x = \"pi%2F4\"  or  x = \"3pi%2F4\". \r\n" );
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document.write( "   In any case, tan(x) = 1  and  cot(x) = 1.\r\n" );
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document.write( "       So, we proved that  if  tan(x) + cot(x) = 2  then  tan(x) = 1  and  cot(x) = 1.\r\n" );
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document.write( "2.  Having this, you have  \"tan%5E17%28x%29+%2B+cot%5E17%28x%29\" = \"1%5E17+%2B+1%5E17\" = 1 + 1 = 2.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer.  if tan(x) + cot(x) = 2  then  \"tan%5E17%28x%29+%2B+cot%5E17%28x%29\" = 2.\r
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