document.write( "Question 95412: The ratio of the areas of two triangles is 8 to 5. The altitude of one triangle is 5 centimeters more than the altitude of the other while the bases are each equal to 10 centimeters. Find the altitude of each triangle.\r
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\n" ); document.write( "\n" ); document.write( "(I have tried to convert the area into an altitude so both sides will be equal, but I am not sure what to do to solve it like that.)
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Algebra.Com's Answer #69511 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The ratio of the areas of two triangles is 8 to 5. The altitude of one triangle is 5 centimeters more than the altitude of the other while the bases are each equal to 10 centimeters. Find the altitude of each triangle.
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\n" ); document.write( "The area of triangle = .5*b*h
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\n" ); document.write( "triangle 1
\n" ); document.write( "A1 = .5(10)h
\n" ); document.write( "A1 = 5h
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\n" ); document.write( "Triangle 2:
\n" ); document.write( "A2 = .5(10)(h+5)
\n" ); document.write( "A2 = 5(h+5)
\n" ); document.write( "A2 = (5h + 25)
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\n" ); document.write( "The problem tells us that: \"8%2F5\" = \"A2%2FA1\"
\n" ); document.write( "or
\n" ); document.write( "\"8%2F5\" = \"%28%285h%2B25%29%29%2F%285h%29\"
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\n" ); document.write( "Cross multiply:
\n" ); document.write( "8(5h) = 5(5h+25)
\n" ); document.write( "40h = 25h + 125
\n" ); document.write( "40h - 25h = 125
\n" ); document.write( "15h = 125
\n" ); document.write( "h = 125/15
\n" ); document.write( "h = 25/3 = 8.333 cm, triangle 1 altitude
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\n" ); document.write( "8.333 + 5 = 13.333 cm, triangle 2 altitude
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\n" ); document.write( "Check solutions by finding the areas:
\n" ); document.write( "A1 = .5*10*8.333 = 41.665
\n" ); document.write( "A2 = .5*10*13.333 = 66.665
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\n" ); document.write( "\"66.665%2F41.665\" = 1.6 = \"8%2F5\"\r
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