document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081027>Question 1081027</A>: <I><SPAN STYLE=\"word-break: break-all;\"> below is a rectangle. if the perimeter is 36m, what is area, b (x+1)m, l(x+5)m </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695089 by </B><A HREF=/tutors/aboutme.mpl?userid=amfagge92><B>amfagge92(93)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amfagge92><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amfagge92><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(l+b) --Perimeter of rectangle<BR>\n" );
document.write( "b=x+1  l=x+5<BR>\n" );
document.write( " &#8658;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28x%2B1%2Bx%2B5%29=36 ALIGN=MIDDLE  ALT=\"2%28x%2B1%2Bx%2B5%29=36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "&#8658;4x+12=36<BR>\n" );
document.write( "  x=6<BR>\n" );
document.write( "&#8756; area of the rectangle<BR>\n" );
document.write( " =l*b=11*7=77m^2<BR>\n" );
document.write( "check:Perimeter=2(7+11)=36m<BR>\n" );
document.write( "      </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );