document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95478>Question 95478</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130488100/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A man deposited $6800 into two accounts. One account earns interest at 8% and the other at 10.5%. The total interest for one year is $669. Find the amount deposited in each account. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69508 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man deposited $6800 into two accounts. One account earns interest at 8% and the other at 10.5%. The total interest for one year is $669. Find the amount deposited in each account.<BR>\n" );
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document.write( "Let amount invested at 8% be x; interest on this is 0.08x dollars<BR>\n" );
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document.write( "Amt invested at 10.5% is \"6800-x\"; interest on this is 714-0.105x dollars<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "interest + interest = 669 dollars<BR>\n" );
document.write( "0.08x + 714-0.105x = 669<BR>\n" );
document.write( "-0.025x = -45<BR>\n" );
document.write( "x = $1800.00 (amount invested at 8%)<BR>\n" );
document.write( "6800-x = $5000 (amount invested at 10.5%<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );