document.write( "Question 1080922: A northbound train left at midnight. Three hours later, a southbound train left the same station. \r
\n" ); document.write( "\n" ); document.write( "At 6 a.m. the two trains were 330 miles apart. Find the rate of each train if the northbound train traveled 10 miles per hour faster than the southbound train.\r
\n" ); document.write( "\n" ); document.write( "Draw graph to display problem.
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Algebra.Com's Answer #695019 by MathTherapy(10555)\"\" \"About 
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A northbound train left at midnight. Three hours later, a southbound train left the same station. \r
\n" ); document.write( "\n" ); document.write( "At 6 a.m. the two trains were 330 miles apart. Find the rate of each train if the northbound train traveled 10 miles per hour faster than the southbound train.\r
\n" ); document.write( "\n" ); document.write( "Draw graph to display problem.
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Let the speed of the northbound train, be S
\n" ); document.write( "Then the speed of the southbound train = S - 10
\n" ); document.write( "Six (6) hours (midnight - 6:00 a.m.) after leaving, the northbound train covered a distance of 6S miles
\n" ); document.write( "Three (3) hours (3:00 a.m. - 6:00 a.m.) after leaving, the southbound train covered a distance of 3(S - 10), or 3S - 30 miles
\n" ); document.write( "Since they were 330 mile apart at 6:00 a.m., we get the following DISTANCE equation: 6S + 3S - 30 = 330
\n" ); document.write( "9S = 360
\n" ); document.write( "S, or speed of northbound train = \"highlight_green%28matrix%281%2C4%2C+360%2F9%2C+%22=%22%2C+40%2C+%22mph%22%29%29\"
\n" ); document.write( "Now, subtract 10 from 40 to get the southbound train's speed.
\n" ); document.write( "That's it!! Simple enough, right?
\n" ); document.write( "Now that the hard part is done, you should be able to graph it. I can't do everything now, can I?
\n" ); document.write( "Try it! How else will you learn? \n" ); document.write( "
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