document.write( "Question 1080944: In a circuit, the electric current (in amperes) varies inversely as the resistance (in ohms). If the current is 40 amperes when the resistance is 4 ohms, find the current when the resistance is 5 ohms \n" ); document.write( "

Algebra.Com's Answer #695018 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
ain fact, Ohm's law is:
\n" ); document.write( " $\"+E+=+I%2AR+\"$ where
\n" ); document.write( " $\"+E+=+voltage+\"$ volts
\n" ); document.write( " $\"+I+=+current+\"$ amps
\n" ); document.write( " $\"+R+=+resistance+\"$ ohms
\n" ); document.write( "--------------------
\n" ); document.write( "If I rewrite this as:
\n" ); document.write( " $\"+I+=+E%2A%281%2FR%29+\"$ , then
\n" ); document.write( " $\"+E+\"$ becomes the constant
\n" ); document.write( "of proportionality
\n" ); document.write( "--------------------------
\n" ); document.write( "case 1:
\n" ); document.write( " $\"+40+=+E%2A%281%2F4+%29+\"$
\n" ); document.write( " $\"+E+=+160+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "case 2:
\n" ); document.write( " $\"+I+=+E%2A%281%2F5%29+\"$
\n" ); document.write( " $\"+I+=+160%2A%281%2F5%29+\"$
\n" ); document.write( " $\"+I+=+32+\"$ amperes\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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