document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080912>Question 1080912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The braking distance D in feet required to stop a car traveling x miles per hour on&#8203; dry, level pavement can be approximated by Upper D equals one sixteenth x squared D=<BR>\n" );
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document.write( "16x2.<BR>\n" );
document.write( "&#8203;(a) Calculate the braking distance for 3030 miles per hour and 7070 miles per hour. How do your answers&#8203; compare? <BR>\n" );
document.write( "&#8203;(b) If the braking distance is 4949 &#8203;feet, estimate the speed of the car.<BR>\n" );
document.write( "&#8203;(c) Use a calculator to solve part&#8203; (b) numerically. Do your answers&#8203; agree? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695016 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The braking distance D in feet required to stop a car traveling x miles per hour on dry, level pavement can be approximated by Upper D equals one sixteenth x squared: D = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F16 ALIGN=MIDDLE  ALT=\"1%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" >x^2.<BR>\n" );
document.write( " (a) Calculate the braking distance for 30 miles per hour and 70 miles per hour. How do your answers compare?<BR>\n" );
document.write( "D = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F16 ALIGN=MIDDLE  ALT=\"1%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" >*30^2<BR>\n" );
document.write( "D = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=900%2F16 ALIGN=MIDDLE  ALT=\"900%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "D = 56.25 ft<BR>\n" );
document.write( "&<BR>\n" );
document.write( "D = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F16 ALIGN=MIDDLE  ALT=\"1%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" >*70^2<BR>\n" );
document.write( "D = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4900%2F16 ALIGN=MIDDLE  ALT=\"4900%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "D =  326.67ft<BR>\n" );
document.write( ":<BR>\n" );
document.write( "(b) If the braking distance is 49 feet, estimate the speed of the car.<BR>\n" );
document.write( "Estimate 27 mph<BR>\n" );
document.write( " (c) Use a calculator to solve part (b) numerically. Do your answers  agree? <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F16 ALIGN=MIDDLE  ALT=\"1%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" >x^2 = 49<BR>\n" );
document.write( "x^2 = 49 * 16<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28784%29 ALIGN=MIDDLE  ALT=\"sqrt%28784%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 28 mph<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );