document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13554>Question 13554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two hot dogs and one hamburger cost $3.39.  Three hot dogs and three hamburgers cost $6.57.  What is the cost of one hot dog? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6950 by </B><A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><B>LilSkittleMd(119)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d=hotdogs; h=hamburger<BR>\n" );
document.write( "The two equations are<BR>\n" );
document.write( "2d+h=3.39<BR>\n" );
document.write( "3d+3h=6.57<BR>\n" );
document.write( "You can use the substitution method to solve this. Take the first equation and solve for h. The equation for that is:<BR>\n" );
document.write( "h=-2d+3.39<BR>\n" );
document.write( "Susbstitute that into the second equation<BR>\n" );
document.write( "3d+3(-2d+3.39)=6.57<BR>\n" );
document.write( "3d-6d+10.17=6.57<BR>\n" );
document.write( "-3d=-3.6<BR>\n" );
document.write( "d=1.2<BR>\n" );
document.write( "The cost of one hotdog is $1.20 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );