document.write( "Question 1857: Solve by factoring x^2=13x+48 and x^2-x-6=0 \n" ); document.write( "

Algebra.Com's Answer #695 by longjonsilver(2297) $\"\"$ $\"About$

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1. write it as everything = 0, so\r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2+-+13x+-+48+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28x+-+16%29%28x+%2B+3%29+=+0\"$ because (-16)(+3) is -48 and (-16+3)is -13
\n" ); document.write( "so 2 things multiplied give zero. THerefore one of them HAS to be zero. Which one? either, hence 2 possible answers... x-16=0 or x+3=0\r
\n" ); document.write( "\n" ); document.write( "hence x=16 or x=-3\r
\n" ); document.write( "\n" ); document.write( "2. $\"x%5E2+-+x+-+6+=+0\"$
\n" ); document.write( "(x-3)(x+2) = 0
\n" ); document.write( "therefore x-3=0 OR x+2=0\r
\n" ); document.write( "\n" ); document.write( "hence x=3 OR x=-2\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon \n" ); document.write( "

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