document.write( "Question 1080914: 600 liters of 50% alcohol solution was diluted to make a 40% alcohol solution. How many liters of the 50% solution needed to be replaced by pure water in order to bring the alcohol concentration down to 40% \n" ); document.write( "
Algebra.Com's Answer #694997 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let n be the amount of pure water to be added. Then: \n" ); document.write( ".5(600)=.4(600+n) \n" ); document.write( "300=240+.4n \n" ); document.write( "60=.4n \n" ); document.write( "n=150 liters of pure water needs to be added. ☺☺☺☺ \n" ); document.write( " \n" ); document.write( " |