document.write( "Question 1080914: 600 liters of 50% alcohol solution was diluted to make a 40% alcohol solution. How many liters of the 50% solution needed to be replaced by pure water in order to bring the alcohol concentration down to 40% \n" ); document.write( "
Algebra.Com's Answer #694997 by jorel1380(3719)\"\" \"About 
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Let n be the amount of pure water to be added. Then:
\n" ); document.write( ".5(600)=.4(600+n)
\n" ); document.write( "300=240+.4n
\n" ); document.write( "60=.4n
\n" ); document.write( "n=150 liters of pure water needs to be added. ☺☺☺☺
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