document.write( "Question 1080793: how do i find the polar form of i(sqrt6 - sqrt2i) with the argument theta between 0 and 2pi? \n" ); document.write( "

Algebra.Com's Answer #694990 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"i%28sqrt%286%29+-+sqrt%282%29i%29=sqrt%286%29%2Ai+%2B+sqrt%282%29\"$
\n" ); document.write( " $\"i%28sqrt%286%29+-+sqrt%282%29i%29=sqrt%282%29%2Bsqrt%286%29%2Ai\"$
\n" ); document.write( ".
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\n" ); document.write( " $\"R%5E2=sqrt%282%29%5E2%2Bsqrt%286%29%5E2\"$
\n" ); document.write( " $\"R%5E2=2%2B6\"$
\n" ); document.write( " $\"R%5E2=8\"$
\n" ); document.write( " $\"R=2sqrt%282%29\"$
\n" ); document.write( "and
\n" ); document.write( " $\"tan%28theta%29=sqrt%286%29%2Fsqrt%282%29\"$
\n" ); document.write( " $\"tan%28theta%29=sqrt%283%29\"$
\n" ); document.write( " $\"theta=pi%2F3\"$ \r
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