document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080894>Question 1080894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2000 cm3 of 4% alcohol was combined with 400 cm3 of 10% alcohol, how much of a solution of 50% alcohol should be added to make a solution of 20% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694966 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 2000 cm3 of 4% alcohol was combined with 400 cm3 of 10% alcohol, how much of a solution of 50% alcohol should be added to make a solution of 20% alcohol?<BR>\n" );
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document.write( "Add C cc's of 50%<BR>\n" );
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document.write( "2000*4 + 400*10 + C*50 = (2000+400+C)*20 = 48000 + 20C<BR>\n" );
document.write( "12000 + 50C = 48000 + 20C<BR>\n" );
document.write( "30C = 36000<BR>\n" );
document.write( "C = 1200 cc's of 50% </SPAN>\n" );
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