document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080890>Question 1080890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I do not understand how to do this: \r<BR>\n" );
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document.write( "How many spherical fishing sinkers with diameter 1 cm could be made by melting a rectangular block of lead 20 cm by 5 cm by 6cm and casting the molten product? \r<BR>\n" );
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document.write( "Please help me and I would really appreciate if you could.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694963 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many spherical fishing sinkers with diameter 1 cm could be made by melting a rectangular block of lead 20 cm by 5 cm by 6cm and casting the molten product? <BR>\n" );
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document.write( "The volume of the block is the product of its dimensions.<BR>\n" );
document.write( "20*5*6 = 600 cc<BR>\n" );
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document.write( "For a sphere:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol+=+4pi%2Ar%5E3%2F3 ALIGN=MIDDLE  ALT=\"Vol+=+4pi%2Ar%5E3%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "r = 0.5 cm<BR>\n" );
document.write( "Vol of each sphere = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2F6 ALIGN=MIDDLE  ALT=\"pi%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > cc<BR>\n" );
document.write( "# of spheres = 600/(pi/6) = 3600/pi </SPAN>\n" );
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