document.write( "Question 1080879: How can you solve a right triangle with two variables?? If a=x+1 b=x c=5 then how do you know? \n" ); document.write( "
Algebra.Com's Answer #694952 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "to solve a right triangle, use Pythagorean theorem \"c%5E2=a%5E2%2Bb%5E2\"
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\n" ); document.write( "If \"a=x%2B1\",\"+b=x\" and \"c=5\", then we have:\r
\n" ); document.write( "\n" ); document.write( "\"5%5E2=%28x%2B1%29%5E2%2Bx%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"25=x%5E2%2B2x%2B1%2Bx%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"0=2x%5E2%2B2x%2B1-25\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B2x-24=0\".......simplify, divide by \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-12=0\"....factor\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-3x%2B4x-12=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-3x%29%2B%284x-12%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28x-3%29%2B4%28x-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+3%29+%28x+%2B+4%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+3%29++=+0\"=>\"x=3\"
\n" ); document.write( "\"%28x+%2B4%29++=+0\"=>\"x=-4\"...........since side of the triangle cannot be negative, disregard \"x=-4\"\r
\n" ); document.write( "\n" ); document.write( "so,\"x=3\"\r
\n" ); document.write( "\n" ); document.write( "then
\n" ); document.write( "\"a=x%2B1\"->\"a=3%2B1\"->\"highlight%28a=4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+b=x\" ->\"highlight%28b=3%29\"\r
\n" ); document.write( "\n" ); document.write( "and \"highlight%28c=5%29\"\r
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