document.write( "Question 1080854: Find the center and radius of the circle whose graph passes through the points (-3,-5), (-9,-13), and (-2,-12). Hint: use the equation x^2+y^2+ax+by+c=0.
\n" ); document.write( "I need help, I have various examples but they skip steps so I don't understand how to solve it.
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Algebra.Com's Answer #694935 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You will make a system of equations with the form of each equation as \"ax%2Bby%2Bc=-%28x%5E2%2By%5E2%29\", because the right-side member will be a computable value for each equation.\r
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\n" ); document.write( "\n" ); document.write( "Each point gives a separate equation.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28-3a-5b%2Bc=-34%2C-9a-13b%2Bc=-250%2C-2a-12b%2Bc=-148%29\"------continue and solve this system for a, b, and c.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28a=12%2Cb=18%2Cc=92%29\"
\n" ); document.write( "(used online calculator at https://matrix.reshish.com/gauss-jordanElimination.php )\r
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\n" ); document.write( "\n" ); document.write( "Use the equation formed using the found coefficients and convert the equation into standard equation form for a circle ( can mean, completing the squares) and read the center and radius from the equation.
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