document.write( "Question 1080661: In an acute triangle ABC, the altitudes AD and CE are drawn. Find the length of the line segment DE if AB = 15 cm, BC = 18 cm, and AD = 10 cm. \n" ); document.write( "
Algebra.Com's Answer #694929 by ikleyn(52797)\"\" \"About 
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\n" ); document.write( "In an acute triangle ABC, the altitudes AD and CE are drawn.
\n" ); document.write( "Find the length of the line segment DE if AB = 15 cm, BC = 18 cm, and AD = 10 cm.
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document.write( "0.  Make a sketch to follow my arguments.\r\n" );
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document.write( "1.  The area of the triangle ABC is\r\n" );
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document.write( "    S = \"%281%2F2%29%2Aabs%28AB%29%2Aabs%28CE%29\" = \"%281%2F2%29%2Aabs%28BC%29%2Aabs%28AD%29\", \r\n" );
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document.write( "    which gives you an equation \r\n" );
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document.write( "    15*|CE| = 18*10.\r\n" );
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document.write( "    It implies |CE| = \"%2818%2A10%29%2F15\" = 12 cm.\r\n" );
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document.write( "2.  Then from the right-angled triangle BCE  |BE| = \"sqrt%28abs%28BC%29%5E2-abs%28CE%29%5E2%29\" = \"sqrt%2818%5E2-12%5E2%29\" = \"sqrt%28180%29\".\r\n" );
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document.write( "3.  From the right-angled triangle ABD  |BD| = \"sqrt%28abs%28AB%29%5E2-abs%28AD%29%5E2%29\" = \"sqrt%2815%5E2-12%5E2%29\" = \"sqrt%2881%29\" = 9.\r\n" );
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document.write( "4.  From the right-angled triangle ABD  cos(B) = \"abs%28BD%29%2Fabs%28AB%29\" = \"9%2F15\" = \"3%2F5\".\r\n" );
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document.write( "5.  Now, to answer the problem's question, apply the cosine law:\r\n" );
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document.write( "    \"abs%28DE%29%5E2\" = \"abs%28BE%29%5E2+%2B+abs%28BD%29%5E2+-+2%2Aabs%28BE%29%2Aabs%28BD%29%2Acos%28B%29\"\r\n" );
document.write( " = \"%28sqrt%28180%29%29%5E2+%2B+9%5E2+-+2%2Asqrt%28180%29%2A9%2A%283%2F5%29\" = \"180+%2B+81+-+2%2Asqrt%28180%29%2A9%2A%283%2F5%29\" = \"261-%282%2A2%2A3%2A9%2A3%2Asqrt%285%29%29%2F5\" = \"261-%28324%2Asqrt%285%29%29%2F5\".\r\n" );
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document.write( "    Hense,  |DE| = \"sqrt%28261-%28324%2Asqrt%285%29%29%2F5%29\" = 10.78 (approximately).\r\n" );
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