document.write( "Question 1080740: dave traveled 280 miles at a certain speed (rate). If he had gone 5 mph faster, the trip would have taken 1 hour less what was his original rate? \n" ); document.write( "
Algebra.Com's Answer #694858 by Alan3354(69443)\"\" \"About 
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dave traveled 280 miles at a certain speed (rate). If he had gone 5 mph faster, the trip would have taken 1 hour less what was his original rate?
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\n" ); document.write( "t = d/r
\n" ); document.write( "t = 280/r = (280/(r+5)) + 1
\n" ); document.write( "280/r = (280 + r + 5)/(r+5)
\n" ); document.write( "280*(r+5) = r^2 + 285r
\n" ); document.write( "280r + 1400 = r^2 + 285r
\n" ); document.write( "r^2 + 5r - 1400 = 0
\n" ); document.write( "(r + 40)*(r - 35) = 0
\n" ); document.write( "r = 35 mi/hr
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