document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080653>Question 1080653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 10 a.m., emma begins walking on a path at a rate of 3 miles per hour. one hour later her friend sara starts at the same point and begins walking on the path at 4 miles per hour. how long will it take sara to catch up to emma on the path? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694770 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance that Emma has walked is rate* time=3mph * x hours or 3x miles.<BR>\n" );
document.write( "For Sara, it is 4 mph * (x-1) hours, since she started an hour behind, or 4x-4 miles.<BR>\n" );
document.write( "Those two are equal since she caught up.<BR>\n" );
document.write( "3x=4x-4<BR>\n" );
document.write( "-x=-4<BR>\n" );
document.write( "x=4 hours<BR>\n" );
document.write( "Emma walked 12 miles in 4 hours<BR>\n" );
document.write( "Sara walked 12 miles in 3 hours.  It took Sara 3 hours to catch up.<BR>\n" );
document.write( "She was gaining at 1 mph and started 3 miles behind--3 hours to catch up.<BR>\n" );
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