document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95417>Question 95417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 8 more than twice the width.  The ratio of length to width is 12 to 5.  Find the length and the width of the rectangle.\r<BR>\n" );
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document.write( "(I tried solving it as 12/5 = 2x+8/2x.  I then cross multiplied and got 5(2x+8)=12(2x).  I used the distributive property to get 5 times 2x+40=12 times 2x.  I do not know how to solve past there though.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69475 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the denominator on the right side of your first equation should be x, not 2x\r<BR>\n" );
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document.write( "5(2x+8)=12x ... 10x+40=12x ... 40=2x ... x=20\r<BR>\n" );
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document.write( "length=48, width=20 </SPAN>\n" );
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