document.write( "Question 95323: Lucia's aunt is now three times as old as Lucia. Fifteen years ago, her aunt was five times as old as Lucia. How old are Lucia and her aunt?
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Algebra.Com's Answer #69474 by ankor@dixie-net.com(22740)\"\" \"About 
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Lucia's aunt is now three times as old as Lucia. Fifteen years ago, her aunt was five times as old as Lucia. How old are Lucia and her aunt?
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\n" ); document.write( "Let x = Lucia's age now
\n" ); document.write( "Then
\n" ); document.write( "3x = Auntie's age now
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\n" ); document.write( "15 years ago they would be:
\n" ); document.write( "(x-15) = Lucia
\n" ); document.write( "and
\n" ); document.write( "(3x-15) = Auntie
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\n" ); document.write( "It says,\"15 yrs ago aunt was five times as old as Lucia.\"
\n" ); document.write( "(3x-15) = 5(x-15)
\n" ); document.write( "3x - 15 = 5x - 75
\n" ); document.write( "3x - 5x = -75 + 15
\n" ); document.write( "-2x = -60
\n" ); document.write( "x = -60/-2
\n" ); document.write( "x = +30 yrs is Lucia's age now
\n" ); document.write( "Then
\n" ); document.write( "3(30) = 90 yrs is Auntie's age now.
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\n" ); document.write( "Check solutions by looking at their ages 15 years ago
\n" ); document.write( "Lucia = 15 years
\n" ); document.write( "Auntie = 75 years which is 5 times 15 years\r
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