document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080611>Question 1080611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> https://www.usatestprep.com/modules/gallery/files/23/2384/2384.jpg\r<BR>\n" );
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document.write( " Choose the correct formula for the function g.<BR>\n" );
document.write( "A)	g(x) = 2x + 3 + 2	<BR>\n" );
document.write( "B)	g(x) = 2x + 3 - 2	<BR>\n" );
document.write( "C)	g(x) = 2x - 3 + 2	<BR>\n" );
document.write( "D)	g(x) = 2x - 3 - 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694723 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^(x-3)+2<BR>\n" );
document.write( "This is different from the 2x-3+2, C, but if one uses that as an exponential, then it works.  The function is shifted upward 2 units, so only A and C are possible.<BR>\n" );
document.write( "The function reaches 3, 1 unit above 2, when x=3.  The value of the x raised to a power is 1, which means the power has to be 0.  If x=3, than 3 has to be subtracted to make x^(value)=1. </SPAN>\n" );
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