document.write( "Question 1080607: Find the area of the shaded figure, rounded to two decimals. (Assume x = 2 and y = 6.)\r
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\n" ); document.write( "\n" ); document.write( "http://www.webassign.net/sprecalc6/6-6-034-alt.gif\r
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Algebra.Com's Answer #694721 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
given: \"x+=+2\" and \"y+=+6\" and two equilateral triangles\r
\n" ); document.write( "\n" ); document.write( "You have two equilateral triangles (you know this since two of the three sides have a length of \"\"y\"\" in each triangle.\r
\n" ); document.write( "\n" ); document.write( "Both triangles are the same.\r
\n" ); document.write( "\n" ); document.write( "To get the area, we need to know the height. We know the base is \"x=2\", but not the height. \r
\n" ); document.write( "\n" ); document.write( "Altitude of the shaded isosceles triangle:
\n" ); document.write( "\"h%5E2+=+y%5E2+%2B+%28x%2F2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"h+=+sqrt%28y%5E2+%2B+%28x%2F2%29%5E2%29\"..........\"x=2\" and \"y=6\"\r
\n" ); document.write( "\n" ); document.write( "\"h+=+sqrt%286%5E2+%2B+%282%2F2%29%5E2%29\"
\n" ); document.write( "\"h+=+sqrt%2836%2B+1%29\"
\n" ); document.write( "\"h+=+sqrt%2837%29\"
\n" ); document.write( "\"h+=+6.08\"\r
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\n" ); document.write( "\n" ); document.write( "Surface area of the shaded one isosceles triangle:\r
\n" ); document.write( "\n" ); document.write( "\"A%5B1%5D=+%281%2F2%29hx\"\r
\n" ); document.write( "\n" ); document.write( "Surface area of the whole shaded figure:
\n" ); document.write( "\"A+=+2A%5B1%5D\"
\n" ); document.write( "so,
\n" ); document.write( "\"A+=++2%281%2F2%29hx\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+hx\".............plug in values for \"h+=+6.08\" and \"x=2\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+6.08%2A2\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+12.16\"\r
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