document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080607>Question 1080607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the shaded figure, rounded to two decimals. (Assume x = 2 and y = 6.)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "http://www.webassign.net/sprecalc6/6-6-034-alt.gif\r<BR>\n" );
document.write( "\n" );
document.write( "link to figure </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694720 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If y is the side<BR>\n" );
document.write( "the area is 5 parts, the area of the base, x^2=4, plus 4 times the area of the faces.  The height of a face is a straight line drawn to bisect the base.  The triangle formed has hypotenuse 6, base 1 (bisected), and altitude  sqrt (35). (Pythagorean theorem 1^2+x^2=6^2)<BR>\n" );
document.write( "The area of each face is (1/2)bh=(1/2)*2* sqrt (35)=sqrt (35)<BR>\n" );
document.write( "There are 4 of them so the area of the faces collectively is 4 sqrt (35)=23.66<BR>\n" );
document.write( "Add to that the 4 above and the area is 27.66.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );