document.write( "Question 1080608: a man invests a certain amount of money at 2% interest and $800 more than that amount another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #694716 by Boreal(15235)\"\" \"About 
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x at 2%
\n" ); document.write( "x+800 at 4%
\n" ); document.write( ".02x+.04(800+x)=92
\n" ); document.write( ".06x+32=92
\n" ); document.write( ".06x=60
\n" ); document.write( "multiply both sides by 100
\n" ); document.write( "6x=6000
\n" ); document.write( "x=$1000@2@=$20.
\n" ); document.write( "x+800=$1800@4%=$72
\n" ); document.write( "Total is $92.
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