document.write( "Question 1080608: a man invests a certain amount of money at 2% interest and $800 more than that amount another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #694716 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x at 2% \n" ); document.write( "x+800 at 4% \n" ); document.write( ".02x+.04(800+x)=92 \n" ); document.write( ".06x+32=92 \n" ); document.write( ".06x=60 \n" ); document.write( "multiply both sides by 100 \n" ); document.write( "6x=6000 \n" ); document.write( "x=$1000@2@=$20. \n" ); document.write( "x+800=$1800@4%=$72 \n" ); document.write( "Total is $92. \n" ); document.write( " \n" ); document.write( " |