document.write( "Question 1080597: What is the eccentricity of this function?
\n" ); document.write( "r= 4/-2-6sinϴ or https://s1.postimg.org/ht0n7b1gv/3_4.png
\n" ); document.write( "A.) 2
\n" ); document.write( "B.) 2/3
\n" ); document.write( "C.) 3
\n" ); document.write( "D.) 6
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Algebra.Com's Answer #694711 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
general formula: \"r+=ed%2F%281-e%2Asin%28theta%29%29\" where \"e\" is the eccentricity, directrix is \"d\" \r
\n" ); document.write( "\n" ); document.write( "\"r=+4%2F%28-2-6sin%28theta%29+%29\"......simplify first\r
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\n" ); document.write( "\n" ); document.write( "\"r=+4%2F-2%281%2B3sin%28theta%29+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r=+-cross%284%292%2Fcross%282%29%281%2B3sin%28theta%29+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r=+-2%2F%281%2B3sin%28theta%29+%29\"\r
\n" ); document.write( "\n" ); document.write( "=>\"+e=3\"\r
\n" ); document.write( "\n" ); document.write( "\"e%3E+1\" , so the conic is a hyperbola\r
\n" ); document.write( "\n" ); document.write( "answer is: C.) \"3\"\r
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