document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080408>Question 1080408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the inverse of f(x)=-3+ln(x-5). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694533 by </B><A HREF=/tutors/aboutme.mpl?userid=rapture><B>rapture(86)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapture><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapture><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = -3+ln(x-5)\r<BR>\n" );
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document.write( "Let f(x) = y\r<BR>\n" );
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document.write( "y = -3+ln(x-5)\r<BR>\n" );
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document.write( "Exchange x and y\r<BR>\n" );
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document.write( "x = -3+ln(y-5)\r<BR>\n" );
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document.write( "Add 3 to both sides.\r<BR>\n" );
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document.write( "x + 3 = ln(y - 5)\r<BR>\n" );
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document.write( "Raise both sides with e as the base.\r<BR>\n" );
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document.write( "e^(x + 3) = e^(ln(y - 5))\r<BR>\n" );
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document.write( "e^(x + 3) = y - 5\r<BR>\n" );
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document.write( "Add 5 to both sides.\r<BR>\n" );
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document.write( "e^(x + 3) + 5 = y\r<BR>\n" );
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document.write( "Replace y with the inverse notation.\r<BR>\n" );
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document.write( "Answer: f^(-1) x = e^(x + 3) + 5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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