document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080333>Question 1080333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi Guys\r<BR>\n" );
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document.write( "Here is my question<BR>\n" );
document.write( "the sum of two numbers is twice their difference, and one number is five more than the 2 numbers. find the 2 numbers.<BR>\n" );
document.write( "so far I have<BR>\n" );
document.write( "eq1 is<BR>\n" );
document.write( "x+y = 2(x-Y)<BR>\n" );
document.write( "x=3y\r<BR>\n" );
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document.write( "eq2 i'm not so sure<BR>\n" );
document.write( "x= y+5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694493 by </B><A HREF=/tutors/aboutme.mpl?userid=kvijioct><B>kvijioct(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kvijioct><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First Condition<BR>\n" );
document.write( "x+y=2(x-y) <BR>\n" );
document.write( "x+y=2x-2y<BR>\n" );
document.write( "x=3y------------Eqn 1.\r<BR>\n" );
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document.write( "Second Condition - This condition is not clear in the given question-one number is 5 more than the 2 numbers. I have assumed it to be 'one number is 5 more than the second number' and have solved it below.\r<BR>\n" );
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document.write( "x=y+5<BR>\n" );
document.write( "3y=y+5  (Substituting for 'x' from Eqn 1)<BR>\n" );
document.write( "2y=5<BR>\n" );
document.write( "y=5/2=2.5\r<BR>\n" );
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document.write( "So, x=3y<BR>\n" );
document.write( "     =3*2.5<BR>\n" );
document.write( "     =7.5\r<BR>\n" );
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document.write( "So, the solution is x=7.5, y=2.5<BR>\n" );
document.write( " </SPAN>\n" );
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