document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95432>Question 95432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering how you solvea system of euqations problem. The problem is 8x+3y=26<BR>\n" );
document.write( "2x=y-4<BR>\n" );
document.write( "   Thanks fo much for you help = ) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69447 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Add 4 to both sides of the 2nd equation. y=2x+4<BR>\n" );
document.write( "substitute 2x+4 for y in the 1st equation. 8x+3(2x+4)=26<BR>\n" );
document.write( "8x+6x+12=26<BR>\n" );
document.write( "subtract 12 from both sides. 14x=14<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "substitute 1 for x in the 2nd equation. 2=y-4<BR>\n" );
document.write( "add 4 to both sides. y=6<BR>\n" );
document.write( "EdJones </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );