document.write( "Question 1080311: the average age of a brother and sister was 35 years,at 5 years ago.what will be their average age at present?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #694466 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
y, Brother
\n" ); document.write( "x, Sister\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Description:\"%28%28y-5%29%2B%28x-5%29%29%2F2=35\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"%28y%2Bx-10%29%2F2=35\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2Bx-10=70\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2Bx=80\", total of their ages now.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"80%2F2=highlight%2840%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Average of will move along with the age of each in the same way.
\n" ); document.write( "
\n" );