document.write( "Question 95432: I was wondering how you solvea system of euqations problem. The problem is 8x+3y=26
\n" ); document.write( "2x=y-4
\n" ); document.write( " Thanks fo much for you help = )
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Algebra.Com's Answer #69445 by kiljoy(51)\"\" \"About 
You can put this solution on YOUR website!
You can do this a couple ways. Let's solve this by substitution. First we take an equation and solve for one of the variables. In this case We're going to use your second equation \"+2x=y-4\" and solve for y. We'll plug the y value then into the second equation.\r
\n" ); document.write( "\n" ); document.write( "\"2x=y-4\"
\n" ); document.write( "\"-y=-2x-4\"
\n" ); document.write( "\"y=2x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "Now we'll substitute this for y in the first equation.
\n" ); document.write( "\"8x%2B3y=26\"
\n" ); document.write( "\"8x%2B3%282x%2B4%29=26\"
\n" ); document.write( "\"8x%2B6x%2B12=26\"
\n" ); document.write( "\"14x=14\"
\n" ); document.write( "\"x=1\"\r
\n" ); document.write( "\n" ); document.write( "Now plug in the x value into either equation to get the y value.
\n" ); document.write( "\"2x=y-4\"
\n" ); document.write( "\"2%281%29=y-4\"
\n" ); document.write( "\"2%2B4=y\"
\n" ); document.write( "\"y=6\"\r
\n" ); document.write( "\n" ); document.write( "This gives us the solution (1,6).\r
\n" ); document.write( "\n" ); document.write( "To check it just plug both values into either equation.
\n" ); document.write( "\"8%281%29%2B3%286%29=26\"
\n" ); document.write( "\"8%2B18=26\"
\n" ); document.write( "\"26=26\"
\n" ); document.write( "
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