document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080243>Question 1080243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangular prism has base edges 4cm, 6cm, and 7cm long. Its lateral area is 408cm^2. What is the height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694431 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the triangle base is P = a+b+c = 4+6+7 = 17 cm long.\r<BR>\n" );
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document.write( "The lateral surface area (abbreviated LSA) of any prism can be found using this formula\r<BR>\n" );
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document.write( "LSA = P*h\r<BR>\n" );
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document.write( "where P is the perimeter along the base and h is the height of the prism. <BR>\n" );
document.write( "We're given the lateral area of 408, so LSA = 408. <BR>\n" );
document.write( "Let's use that LSA value, along with P = 17 as well to solve for h.\r<BR>\n" );
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document.write( "LSA = P*h<BR>\n" );
document.write( "408 = 17*h<BR>\n" );
document.write( "408/17 = 17*h/17<BR>\n" );
document.write( "24 = h<BR>\n" );
document.write( "h = 24\r<BR>\n" );
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document.write( "<font color=red>The height is 24 centimeters</font><BR>\n" );
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