document.write( "Question 1080216: Given f(x) = x + 1 and g(x) = x – 1, find (fg)(x).\r
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document.write( "2x
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document.write( "x^2 – 1
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document.write( "x^2 + 2x – 1
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document.write( "-2
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Algebra.Com's Answer #694412 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! (fg)(x) is the same as (f*g)(x) or f(x)*g(x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means we are multiplying the functions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) = (f*g)(x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) = f(x)*g(x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) = [ f(x) ] * [ g(x) ]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) = [ x+1 ] * [ x-1 ]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) = x(x-1) + 1(x-1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) = x^2 - x + x - 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(fg)(x) = x^2 - 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the final answer is choice B) x^2 - 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: You can use the difference of squares formula as a shortcut. \n" ); document.write( " |