document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1072885>Question 1072885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The total oil reserve at the Kranka oil field is 250 tonnes. The annual consumption is 20 tonnes which increases by 2% per annum. How long will it take for the oil to be used up? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694393 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The initial consumption is 20 tonnes, which increases by 2% per year. To sum up the series, we have:<BR>\n" );
document.write( "250=20&#931;(1.02)^n where n goes from 0 to ?. 250/20=12.5, so<BR>\n" );
document.write( "12.5=&#931;(1.02)^n<BR>\n" );
document.write( "Plugging in different values for n, we find that n equals a little over 11 years before the oil reserve is used up. </SPAN>\n" );
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