document.write( "Question 1080137: A cyclist rode the first 24 mile portion of his workout at a constant speed. For the 16 mile cooldown portion of his​ workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the​ cyclist's speed during the first portion and find his speed during the cooldown portion. \n" ); document.write( "
Algebra.Com's Answer #694352 by ikleyn(52906)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "Your equation is\r\n" );
document.write( "\r\n" );
document.write( "\"24%2Fr\" = \"16%2F%28r-4%29\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Cross multiply:\r\n" );
document.write( "\r\n" );
document.write( "24*(r-4) = 16r,\r\n" );
document.write( "\r\n" );
document.write( "24r - 96 = 16r  --->  24r - 16r = 96  ---->  8r = 96  --->  r = \"96%2F8\" = 12.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer. The speed during the first portion is 12 miles per hour\r\n" );
document.write( "         and the speed during the rest of the trip was 12-4 = 8 mph.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );