document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1080049>Question 1080049</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Consider the following probability distribution: x:    0       1         2          3       4<BR>\n" );
document.write( "                                                                   p(x):  0.1     0.4      0.3       0.1     0.1<BR>\n" );
document.write( " (a) Find the mean of the distribution.<BR>\n" );
document.write( " (b) Find the variance.<BR>\n" );
document.write( " (c) Find the standard deviation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #694272 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=694272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> E(X)=mean=0*0.1+1*0.4+2*0.3+3*0.1+4*0.1=1.7<BR>\n" );
document.write( "V(X)=1.7^2*0.1+0.7^2*0.4+0.3^2*0.3+1.3^2*0.1+2.3^2*0.1, or different from mean squared * probability and add, which is 0.289+0.196+0.027+0.169+0.529=1.21<BR>\n" );
document.write( "Std is sqrt (V)=1.1<BR>\n" );
document.write( "mean 1.7, variance 1.21, sd 1.1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );